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March 6, 2024
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The Highest Common Factor (HCF), also known as the Greatest Common Divisor (GCD), of two or more numbers is the largest positive integer that divides each of the numbers without leaving a remainder. To find the HCF of two numbers, various methods can be used, such as prime factorization, the Euclidean Algorithm, or brute-force checking of common factors. The HCF is crucial in simplifying fractions, finding equivalent fractions, and solving certain mathematical problems.
Example: Consider finding the HCF of the numbers 36 and 60.
Explanation of the Euclidean Algorithm:
Therefore, the HCF of 36 and 60 is 12.
This method efficiently finds the HCF by repeatedly dividing the larger number by the smaller number and replacing the numbers until the remainder becomes zero, giving the HCF.
More Description
Program to find the HCF of Number
num1
with the value 36 and num2
with the value 60.hcf
with the value 1.i
equals 1 up to the minimum of num1
and num2
, which is 36.num1
and num2
are divisible by the current value of i
.i
is a divisor of both num1
and num2
, update hcf
to the value of i
.i
reaches the minimum of num1
and num2
.hcf
will contain the highest common factor of num1
and num2
, which is 12 in this case.hcf
, which is 12.This approach checks all numbers from 1 up to the minimum of num1
and num2
to find their highest common factor. While it’s simple, it may not be efficient for large numbers compared to other methods like prime factorization or the Euclidean Algorithm.
#include <stdio.h>
int main() {
int num1 = 36;
int num2 = 60;
int hcf = 1;
for (int i = 1; i <= (num1 < num2 ? num1 : num2); i++) {
if (num1 % i == 0 && num2 % i == 0) {
hcf = i;
}
}
printf("HCF OF Number %d and %d is %d\n", num1, num2, hcf);
return 0;
}
HCF OF Number 36 and 60 is 12
#include <iostream>
using namespace std;
int main() {
int num1 = 36;
int num2 = 60;
int hcf = 1;
for (int i = 1; i <= min(num1, num2); i++) {
if (num1 % i == 0 && num2 % i == 0) {
hcf = i;
}
}
cout << "HCF OF Number " << num1 << " and " << num2 << " is " << hcf << endl;
return 0;
}
HCF OF Number 36 and 60 is 12
public class Main {
public static void main(String[] args) {
int num1 = 36;
int num2 = 60;
int hcf = 1;
for (int i = 1; i <= Math.min(num1, num2); i++) {
if (num1 % i == 0 && num2 % i == 0) {
hcf = i;
}
}
System.out.println("HCF OF Number " + num1 + " and " + num2 + " is " + hcf);
}
}
HCF OF Number 36 and 60 is 12
num1=36
num2=60
hcf=1
for i in range(1,min(num1,num2)):
if num1%i==0 and num2%i==0:
hcf=i
print("HCF OF Number",num1,"and",num2,"is",hcf)
HCF OF Number 36 and 60 is 12
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